Given:
[HCl] = 3.02 M
So,
[H+] = 3.02 M
use:
pH = -log [H+]
= -log (3.02)
= -0.48
Answer: c
d) 1.7 x 10-4M ) 1.4 x 10' M 8. Find the pH of a 3.02 M HCL solution. a) 7.1 x 10M b ) 1.6 x 10-2M c)-0.48 M
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