Question

can you please explain why did he chose the circled product as a major ?

I only need explaination for part a please

For the following a) Circle the major organic product (1 pt) reaction: b) Provide a mechanism for the initiation and two propagation steps (major only) (5 pts) c) Calculate AH001. AH , and AH (4 pts) d) Which is the rate determining propagation step (1 pt)? Explain (3 pts) e) Does the rate determing step involve an early or a late transition state? (1 pt) Explain (3 pts). 1) Diagram the transition state (3 pts) -H+402 x +365 .. cler Cl.Br. en er He+ & Brice Hprep! +365-431 AH grep 2= +219-241 = -1 26 KI/mol -22 KJ/mol 2 Stran = -126-22= -14851 βανος ΔΣΟ ΔΕΚΔΗ & more exothermic = faster - Prop 2= slower = RDS bec. in exothermic ran energy of T.S. is clarer to energy of reactants (EARLY) is T.S. recenables mectants more than products mol

explaination for part A for both questions please

Answer 1

Solution:

Part A) The given reaction is an example of free radical substitution reaction. Here, reactivity of halogens follow the order as,

I > Br > Cl > F

Thus, iodine is easily substituted H at allylic position due to higher stability of alkene intermediate by allylic double bonds.

Thus,

When Cl-Br is reacted, the major product contains Br group at allylic position.

When I-F is reacted, major product contains I group at allylic position.

BY Br-el marr pwduet I-F matr pwduct H I AMAIC suttukrau