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3. (a) Let (X,Y) have the joint pmf (2 + y + k – 1)! P(X = 1, Y = y) => pip (1- P1 - p2), r!y!(k − 1)! where r, y=0,1,2, ...,

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Solution: - From Given :- p(x=x, Vzy) = ((**9#k-1)} box belo. Po Polk P(x= - Pkpl (1-P1-P2}K Marginal distribution Box La) =Conditional distribution: Conditional prckabinity Hat Y=y quen the ply = y /x=XIe Ply=y, x=x) P(x=x) Ell-P2) a+1(+X) (a2+1) -

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3. (a) Let (X,Y) have the joint pmf (2 + y + k – 1)! P(X = 1, Y = y) => pip (1- P1 - p2), r!y!(k − 1)! where r, y=0,...
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