Solution:
Get the 99% confidence interval in TI 83 as
2ND>VARS>TESTS>T INTERVAL
You get
99% confidence interval for mean as
13404<mu<22396
ANSWER:
13404<mu<22396
Attempt 2 of Unlimted 7.4 Section Exercise Question 18 of 18 (1 point) College tuition: A simple random sample of 4...
College tuition: a simple random sample of 35 colleges and universities in the united states has a mean tuition of $19,400 with a standard deviation of $10,700. Construct a 95% confidence interval for the mean tuition for all colleges and universities in the United States. round the answers to the nearest whole number. A 95% confidence interval for the mean tuition for all colleges and universities is __________________< mean < _____________________
College tuition: A simple random sample of 35 colleges and universities in the United States has a mean tuition of $17,600 with a standard deviation of $10,200. Construct a 90% confidence interval for the mean tuition for all colleges and universities in the United States. Round the answers to the nearest whole number. A 90% confidence interval for the mean tuition for all colleges and universities is h
please solve College tuition: A simple random sample of 40 colleges and universities in the United States has a mean tuition of $18,400 with a standard deviation of $10,600. Construct an 80% confidence interval for the mean tuition for all colleges and universities in the United States. Round the answers to the nearest whole number. An 80% confidence interval for the mean tuition for all colleges and universities is ㄨ 幻
Question 16 of 18 (1 point) Attempt 1 of Unlimited 74 Section Exercise 12 (cal Ages of students: A simple random sample of 110 U.S. college students had a mean age of 23.02 years. Assume the population standard deviation is o = 4.77 years. Construct a 98% confidence interval for the mean age of U.S. college students. Round the answers to two decimal places. A 98% confidence interval for the mean age of U.S. college students is
College Tuition ~ A random sample of 65 two-year colleges in the United States found that the average tuition charged in 2008-2009 was $2,314.12 and a standard deviation of $1,184.68. Note: Numbers are randomized in each instance of this question. Pay attention to the numbers in this question. What is the upper bound for a 95% confidence interval for the actual mean tuition charged in 2008-2009? Give your answer to 4 decimal places. Your Answer:
Question 4 of 18 (1 point) Attempt 2 of Unlimited View question. In a popuR! 7.1 Section Exercise 37-38 A sample of size n = 92 is drawn from a normal population whose standard deviation is a = 5.6. The sample mean is x = 46.06. Part 1 of 2 (a) Construct a 95% confidence interval for Jl. Round the answer to at least two decimal places. A 95% confidence interval for the mean is <u< . Part 2 of...
2. A simple random sample of 15 college students showed a mean credit score of 655 and standard deviation 20. Construct the 99% confidence interval estimate of the mean credit score for all college students. a. State the critical value. b. Compute the margin of error. c. State the confidence interval.
*without using interval functions on calculator* 26. Birth Weights A simple random sample of birth weights in the United States has a mean of 3433 g. The standard deviation of all birth weights is 495 g a. Using a sample size of 75, construct a 95% confidence interval estimate of the mean birth weight in the United States. b. Using a sample size of75,000, construct a 95% confidence interval estimate of the mean birth weight in the United States. c....
Question 9 (4 points) A college admissions officer takes a simple random sample of 104 entering freshmen and computes their mean mathematics SAT score to be 471. Assume the population standard deviation is 121. What is the lower bound of the 99% confidence interval? Round your answer to the nearest integer. Write only a number as your answer.
Question 13 of 18 (1 point) Attempt 1 of Unlimited 7.3 Section Exercise 15-18 Use the given data to construct a 98% confidence interval for the population proportion p. x = 47, n=71 Round the answer to at least three decimal places. The confidence interval is