Question

II(10 pts) State Using simple gas laws, complete the following table. All experiments were performed on the same sample of gas. T(K) P(atm) VL) 265 0.425 297 6.8 0.680 5.0 335 0.425 6.8 Some commercial drain cleaners make use of the following reaction to declar drains

Answer 1

Ideal gas e equateen pv=nRT No.et mols (n) = Step-I: Let us find No. 8 mots of gas n= 0.425 ahm x 6.8L 00821 Lrabnik. molex 265k n = 0.13 mol State - 2 - PanRT = 0.13 m&+0.0821 Calm kme +297 6.8L .:P = 0.49 atin state-3 . T- PV . HR = 0.680 atm x 5:02 - 6 13 ml x 0.0821 Lilators/amol T 320K - U=nRT state-4 V = 0.13X0-0821 X 335 0.425 TEK) v 265 297 320K 335 = 8.4L Petra) Veo) 0.425 6-8 0.470 6-8 0-680 1. So 0.425 8.4