Question

Problem 3 (20 Pts): Calculate latitudes, departures, misclosure, and redistribute misclosure vector Sync Code: 90.50 Traverse Unadiusted Data Azimuth 1250 Pt. 1-2 252.5894 226.36 Pt. 2-3 124.5506 62.72 1200 Pt. 3-1 57.8587 193.70 Coordinates of Pt. 1: 1150 1100 1270.83 1137.98 1050 Here the azimuths have already been calculated. From Azimuth and distance, calculate latitudes, departures, and 1000 the misclosure vector 950 1100 1200 1300 1000 East Misclosure (oE, ON) Sync Code 90.5

please solve all parts of the problem

Answer 1

Latitude = DCos a and Departure = DSina

Where D is the length of the arm of the triangle and a is the azimuth

Pt. 1-2, a = 252.5894, D = 226.36

Latitude = 226.36*Cos(252.5894) = -67.730834

Departure = 226.36*Sin(252.5894) = -215.989314

Pt. 2-3, a = 124.5506, D = 62.72

Latitude = 62.72*Cos(124.5506) = -35.5706339

Departure = 62.72*Sin(124.5506) = 51.657801

Pt. 3-1, a = 57.8587, D = 193.70

Latitude = 193.70*Cos(57.8587) = 103.050156

Departure = 193.70*Sin(57.8587) = 164.013278

Misclosure $\delta$ = ($\delta$E, $\delta$N)

$\delta$E = Sum of Departures = (-215.989314+51.657801+164.013278) = -0.318235

$\delta$N = Sum of Latitudes = (-67.730834+(-35.5706339)+103.050156) = -0.2513119‬

Misclosure $\delta$ = (-0.318235, -0.2513119‬)