Question

A ball is thrown upwards with a speed of 19 m/s. it reaches a hight of 18.4 m above the point of release before it falls back down. Specify down as the positive direction and the initial position as the origin. If the balls position after three seconds is -12.9 meters, what is the distance traveled by the rock? The acceleration due to gravity is 9.8 m/s^2 down. The answer is 23.9 meters, how would i solve this?

Answer 1

haigkt baU doach Jag e . 4m given u- -19 mls , sinco dzecded v- u+at Upwan [3-3.8mb , sice dow n conso pount^ うt= ¡.93877 sec. 1.93877 sec. down wands duredionand Cod! c d -.-12.gm at the end 어 3 seconds 13-4-12-3 m Am : 5.S m tatal distance aveledo thu end 18. 4+ 5.S m = 23.9 n Decondo # dhaa