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the first question is done I need the others
Consider a closed system that cannot do pressure volume work, but rather does work of the form w = (xar The state variables f
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Answer #1

Answer (b)

dU= TdS + XdY

Differentiating the above equation with respect to dY at constant temperature we get,

(dU/dY)T = T * AP/SP) T + X

Answer (d)

U= U(T,Y)

Applying first principle of differentials,

dU= (SUST)Y * dT + (SU/SY)T * dY

For an adiabatic process, dU=0 hence the above equation becomes

(SUST)Y * dT = -  (SU/SY)T * dY

since according to above equation Y and T are oppositely charged, when Y increases T decreases and vice-versa.

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