Q = f(L, K) = 4L0.5K0.5
(a)
Isocost equation: C = wL + rK = 40L + 10K
When C = 400,
400 = 40L + 10K
40 = 4L + K.........(1)
When L = 0, K = 40 (vertical intercept) and when K = 0, L = 40/4 = 10 (horizontal intercept).
When C = 200,
200 = 40L + 10K
20 = 4L + K.........(2)
When L = 0, K = 20 (vertical intercept) and when K = 0, L = 20/4 = 5 (horizontal intercept).
In following graph, AB & CD are isocosts showing (1) and (2) respectively.
(b)
Cost is minimized when MPL/MPK = w/r = 40/10 = 4
MPL = Q/L = 4 x 0.5 x (K/L)0.5
MPK = Q/K = 4 x 0.5 x (L/K)0.5
MPL/MPK = K/L = 4
(c)
Since K/L = 4,
K = 4L
When Q = 40,
4L0.5K0.5 = 40
L0.5K0.5 = 10
Squaring,
LK = 100
L x 4L = 100
L2 = 25
L = 5
K = 4 x 5 = 20
C = 40 x 5 + 10 x 20 = 200 + 200 = 400
In above graph, isoquant is Q0.
(d)
When output is y,
4L0.5K0.5 = y
L0.5K0.5 = y/4
Squaring,
LK = y2 / 16
L x 4L = y2 / 16
L2 = y2 / 64
L = y / 8
K = 4 x (y/8) = y / 2
C = 40 x l + 10 x K = 40 x (y/8) + 10 x (y/2) = 5y + 5y = 10y
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