Question

A16 Two isomers of a cobalt(III) complex are shown below. Which ONE of the following statements is INCORRECT? H2 CH2 ] [NCON I NH₂ H₂N... CO EN IN H2 CI H2 H2N isomer A IL NH₂ isomer B [Co(en)2Cl2]CI (A) Both isomers are 6-coordinate complex cations in solution. (B) Both complexes have six 3d electrons. (C) Chloride is present as a ligand and a counter ion. (D) Isomers A and B are enantiomers. (E) Both complexes have 5-membered chelate rings.

Answer 1

solution was a isomen A (5 membered Chelate ring) icomen B (5 member Chealate sing) souter ce is a counter in which means in # Both isomers are 6-60-ondinate complexe Laction the solution - Connect In Both complece co is in +3 oxiolation state- Co = 15²25²20f35² 3pl 45² 3d C30 - 15² 25² 2pc 35² 3p' 3db option & is correct Both compleer have 3db B. % from present the as above ligand graph and it is clear that ce is cunter in (for Balance the tre chay. & There is a mirror pertion that means So, they can't be So, Toption plane from the sauare planar there is no optical isomerism enantiomer. is incorrect ! 4. kould & is = Co sure. 5 membered ring. correct * 26 W3