Question

solve for xm

iven the equilibrium constantK and Eq. (3) and Eq. (4) then one can find the value of Xm When the laboratory experiment is done (see part B for more details - we are NOT doing the boratory work. We only are doing molecular modeling work. The laboratory work involves fluxing menthone in a mixture of glacial acetic acid and 1.0M hydrochloric acid. After the uilbirium is established where menthone and isomenthone are both present, these molecules ay be extracted and the mixture isolated so the optical rotation of the mixture can be measured. reported results, the experimental optical rotation of the menthone and isomenthone ixture was measured and found to be A=-3.0 degrees. The specific rotation of the ementhone is Ai= +92 degrees and menthone is Am-30 degrees. The measured angle of rotation, A, for this mixture is given by (5) A (Am) (Xm) + (Ai) (Xi) combining with Eq. (4), the above can be written as A (Am) Xm + (Ai ) (1- Xm) (6) Use the information above to calculate the experimental mole fraction of menthone, Xm, an

Answer 1

Am=-30° Ai = +920 tra mole fraction of math mathone fraction of isomerthone Xi = mole = 1 - Xi o A= -3° A = Amxm + Ai (irxm) =) -3° = -30 Xm + 92° (1-Xm) -3° – 92° = xm (-92630) - xm= 950 1220 Xm = 0.78 xi = 1- xm = 0.22 Answer.