Question

For the reaction N2(g) + 3H2(g) = 2NH3(g) what is the value of Ke at 500°C if the equilibrium concentrations are as follows: [H2] = 0.40 M, (N2) = 0.40 M, and (NH3) = 1.9 M Express the equilibrium constant to two significant figures. V AE OE ? Submit Previous Answers Request Answer X Incorrect; Try Again; 4 attempts remaining Set up the equilibrium-constant expression for this reaction using the equilibrium concentrations. The product concentrations a the reactant concentrations are in the denominator. Additionally, the coefficients from the balanced chemical equation become respective concentrations.

Answer 1

1 for N₂(g) + 3H₂(g) → 2NH₂ (g). 0.4M 0.4M 1.9M Kc = [NH3]2 [N2] [Hz]² 1.981.9 044 (0.4) 3 0.0256 Kc = 141.01 = 3.61 04x al I l for - Colg) + H₂O(g) 0.10M 0.34M Kc - colg) + H2(g) 0.26M 0.032 EO] [H2O) [CO2] [Hz] Kc = 0.0612 0.00032 0.18 X 0.34 0.26 X 0.032 Ke = 7.356