Question

3 attempts left Check my work Be sure to answer all parts. Calculate the wavelength (in nm) of light with energy 1.61 x 10-20 J per photon. For light of wavelength 450 nm, calculate the number of photons per joule. x 10 photons/J Enter your answer in scientific notation. Determine the binding energy (in eV) of a metal if the kinetic energy possessed by an ejected electron (using one of the photons with wavelength 450 nm) is 2.93 x 10""'J. eV

Answer 1

Answer : *l. Given, Energy = 1.618 10-20 J/photon. By Planck- &instein relation, E-he, where h=6.63 x 10-34 Is c = 3 1017 umis. ^ d = ^ 6.63 x 1034 J.S. x 3 x 1017 nm/s 1.61 x 1080 J. = 1.23x 104 nm 7 LANSWER. *2 civen, d=450nm. - E= h = 6.63 x 1034 J. J. & 3x 1017 nmis 450 nm E = 4.42 x 10-19 7 ANSWER

*3 KE(electron) = 2.93×10 9 7 / given) kinetic energy of each electron is. equal to difference blw the energy per incident moton & work function. Also, work function is minimum binding energy that needs to be supplied to overcome metal's attraction on the electron. KE(electron) - Elincident photon) - Ametal) corresponds to from * above, 450nm 4.42 x 10-19 J. Hence, b (metal) = = = Elincident photon) -KE. (electron) 4.42 x 10-15 - 2.93 x 10-19 J. 1.49 x 1019 J 0.9299 ev / ANSWER (as 17= 6.242x1018) [Pemetal) =
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