Question

the spar platform shown above has a circular cross section with diameter D (upper part) and 2D (lower part). It is floating in a very deep water.
a. Derive an expression for the natural frequency.1. The spar platform shown above has a circular cross section with diameter D (upper part) and 2D (lower part). It is floatin

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Answer #1

Given, a platform is floating on water for which we need to determine the natural frequency which is stated as simple harmonic equation.

We are going to use newton's second law and buoyancy forces to find SHM.

From the obtained simple harmonic motion equation we find the natural frequency.

The above discussed is represented in the below image:

iven dt? กา H, (De) Nals

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