Question

1. What would be the output of the following MIPS code? .globl main main addu $s7, $0, $ra add $s3, $0,$0 addi $s4, $0, 1 $s5, $0,$0 $s6, save add . data .align 2 .globl save # the next line creates an array of 10 words that can be re ferred to as "save" # the array is initialized to the 10 values after .wo rd # so the first array entry is a 0 and the last entry is a 2 save: .word 0, 0, 0, 0, 0, 0, 0, 6, 3, 2 text Loop: add $t8, $s3, $S3 add add şt9, 0 ($t8) $t9, $s5, Exit bne add $s3, $s3, $s4 Loop Exit: . data .globl messagel .asciiz "nThe value of i is: '" messagel: .text 1i Şv0, 4 Şa0, messagel syscall 1i $v0, 1 Şa0, $0, $s3 add syscall addu Şra, $0, $S Şra $0, $0, $0 add

Answer 1

Note :- the output is written in BOLD format

Before start of Loop :-
$s7 = $ra
$s3 = 0 # index
$s4 = 1   #increment counter
$s5 = 0
$s6 = save = base address of array

In loop (it continues for each element of array untill) :-
$s3 = index of the array
$t8 = element address in loop
$t9 = value of the element pointed
if the value of $t9 is not equal zero then loop breakp and prints the value of index i.e $s3

So, the program prints the index of first non zero value element in the array

Output :-
The value of i is 7