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DQuestion 34 1 pts A5 kg projectile is fired at an angle of 25° above the horizontal. Its initial velocity is 200 m/s and jus

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34)

Change in mechanical energy of projectile is AKE = = m(0 – 12) = 5*5* (1502 – 2002) = -43750 ~ - 44000 J

Answer is -44000 J

35)

For the two blocks initial energy is E; = mgh and final energy is Es = 5mv-

Conserving energy of each block at the top and bottom , E; = Ep = mgh = -mv2 = v= 2gh

Answer They both will have the same speed.

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