Question

A converging lens (f = 14.5 cm) is located 34.0 cm to the left of a diverging lens (f = -5.82 cm). A postage stamp is placed 47.7 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification. (a) Number Units T cm (b) Number units no units

Answer 1

Then , 1/f1 = 1/di1 - 1/d01 (for converging lens)

f1 = 14.5 cm

do1 = -47.7 cm

sol f= 14.5cm (for convering reus) a obje of do, =(-47.20 distance " 1-47.7 cmì form lens formulais LI.! f die doo find di, so, here, f. = 14.5cm dir - Hitam (don--47.7cm) o the contra its 12.7 t + 33.2 691-65 1 = 0.04800 11 1 so di, da = 20-83 cm 0:04 800 so image distance from converging lens, di =20.83cm then given fa=-5.82cm and doz=-(34>20.83) doz = -13.17cm diz doa Por to the

مر = 1 Fa + diz 1 dos fz = -5.82cm doz =-13-17cm die -5.82 die = -18.99 → LE- 0.2477 76.65 دزلي diese diz = -4.037 Cly -0.2477 ve dia= -4.03711 it to the left of the h . diverging lens!! part b) then final magnification is, И= mix м2 fos M=(en)* alias) M= (20783 =13.03.) M=-0.0367 x 0.30653 TM=-0.13 Aug I hope help you!!