An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens. Part A What is th...
An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens.
Part A
What is the focal length of the lens?
Part B
Is the lens converging or diverging?
Part C
If the object is 8.00mm tall, how tall is the image?
Part D
Is it erect or inverted?
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An object is 16.0cm to the left of a lens. The lens forms an image 36.0cm to the right of the lens. Part A What is th...
Constants An object is 16.0 cm to the left of a lens. The lens forms an...
Constants An object is 16.0 cm to the left of a lens. The lens forms an image 36.0 cm to the right of the lens Part A What is the focal length of the lens? Tempistes Symbols Undo redo Pese keyboard shortcuts help Submit Request Answer Part B Is the lens converging or diverging? The lens is converging. The lens is diverging. Previous Answers ✓ Correct Part C If the object is 8.00 mm tall, how tall is the image?...
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm...
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm tall, 17.5 cm to the right of the lens.Part A Determine the position of the object. Part B Determine the size of the object.Part C Is the image erect or inverted? erect invertedPart D Are the object and image on the same side or opposite sides of the lens? The object and image are on the same side. The object and image are on...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
A photographic slide is to the left of a lens. The lens projects an image of...
A photographic slide is to the left of a lens. The lens projects an image of the slide onto a wall 6.01 m to the right of the slide. The image is 84 times the size of the slide. 1) how far is the slide from the lens 2) is the image erect or inverted 3) what is the focal length of the lens 4) is the lens converging or diverging
A converging lens with a focal length of 6.50 cm forms an image of a 3.80...
A converging lens with a focal length of 6.50 cm forms an image of a 3.80 mm -tall real object that is to the left of the lens. The image is 2.10 cm tall and erect. Where are the object and image located? in cm
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length o...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by t...
Part A: A diverging lens has of focal length of 15.0 cm. An object is placed 21 cm to the left of the lens. a) draw a ray diagram showing the situation. b) find the location of the image produced by the lens (mind the signs). Part B: A converging lens is located 30 cm to the right of the previously mentioned diverging lens (part A). As a result, the image you found in part (a) is now instead located...
A converging lens with a focal length of 87.0 cmcm forms an image of a 3.35...
A converging lens with a focal length of 87.0 cmcm forms an image of a 3.35 cmcm -tall real object that is to the left of the lens. The image is 4.75 cmcm tall and inverted. Part A Where are the object and image located in relation to the lens? Express your answers in centimeters separated by a comma. |s||s|, |s′||s′| = nothing cmcm SubmitRequest Answer Part B Is the image real or virtual? Is the image real or virtual?...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a fo...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
A converging lens with a focal length of 8.00 cm forms an image of a 5.60-mm-tall...
A converging lens with a focal length of 8.00 cm forms an image of a 5.60-mm-tall real object that is to the left of the lens. The image is 1.40 cm tall and erect. a) Where is the object located? Follow the sign rules. (express answer with appropriate units) b) Where is the image located? Follow the sign rules. (express answer with appropriate units)
Constants An object is 16.0 cm to the left of a lens. The lens forms an image 36.0 cm to the right of the lens Part A What is the focal length of the lens? Tempistes Symbols Undo redo Pese keyboard shortcuts help Submit Request Answer Part B Is the lens converging or diverging? The lens is converging. The lens is diverging. Previous Answers ✓ Correct Part C If the object is 8.00 mm tall, how tall is the image?...
A diverging lens with a focal length of -47.0 cm forms a virtual image 7.50 mm tall, 17.5 cm to the right of the lens.Part A Determine the position of the object. Part B Determine the size of the object.Part C Is the image erect or inverted? erect invertedPart D Are the object and image on the same side or opposite sides of the lens? The object and image are on the same side. The object and image are on...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
An object 2.02 cm high is placed 40.2 cm to the left of a converging lens having a focal length of 30.5 cm. A diverging lens with a focal length of-20.0 cm is placed 110 cm to the right of the converging lens. (a) Determine the position of the final image. distance location to the right , of the diverging lens (b) Determine the magnification of the final image 128.4 Your response differs from the correct answer by more than...
A 4.0 cm tall object is 5.0 cm in front of a diverging lens with a focal length of -6.0 cm. A converging lens with a focal length of 6.0 cm is located 8.0 cm behind the diverging lens. (As viewed from the side, from left to right, the sequence is object - diverging lens - converging lens - observer. Rays then travel from left to right through the system.) (a) Use ray tracing to draw image 1 and image...
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