Question

Above what Fe2+ concentration will Fe(OH), precipitate from a buffer solution that has a pH of 9.17? The Kp of Fe(OH), is 4.87x10-17 [Fe2+] = 7.20 x10-8

Answer 1

Thes e expression to cakolate the port of the losion is as follows: PHAPOH 14. The value of pH is 9.17 substitute the value in the above expression . pOH = 149,17=4.83 The expression to calculate the ott is as follow OH = 10-port substitute the value in the above expression on = 10-4.83 = 1.480105 m The expression of solubility product corestent of the above expression as follows Ksp = [ Pezt] [one IP Rearrange the above expression to calcola [Fe2+] = ke A [ok]" solubllity produit constant Ksp = 4.87 X10 17 m substitute the vile in the aboue expression [Feet] = 4.87 41017/0.48010572 - 2.22X10