Question

please solve number 5 and 6 using the table.

Part 1: Simple Extraction and Determination of the Distribution Coefficient (Partition Coefficient) for Propionic Acid Between Ether and Water Table 1 (a) Preparation of Propionic Acid (PA) Solution weight PA Volume H2O (g) (e) Titration of Aqueous Propionic Solution After Ether Extraction (b) Titration of Aqueous Propionic Acid Solution Before Ether Extraction Volume PA. Volume NaOH Volume Volume PA Aliquot (mL) aliquot (mL) NaOH (mL) (mL) (mL) 17.30 mL50.00 mL 10-00 mL 10.40ML 4.844a 110 mL Molarity NAOH (M) O.3130 M Calculations: Use the data in Table 1 to perform the following calculations Calculate the molarity of your initial solution of propionic acid in water based on the data in part (a) 1. of your table (total weight of PA used and total volume of water used to dissolve the PA). mol PA स्य.०७9 Molavity(M) motes of saute Liters 0f solution 4.8 44g PA = 0.065388 mde PA PA 0.06538s moles PA O.INL M 0,59444 = 0.594 M IDO mL 1000 mL 2. Calculate the molarity of your initial solution of propionic acid in water based on the data in part (b) of your table (titration of your initial PA solution with NaOH). MNI=M2VE NaOtt M (0.01 t.31 30 mot(0.01g LNaoH PA M(0.01L)= o.00s5 #14 mol mao15514.322703 0.557M22 ate sanocod

Answer 1

6) The partition coefficient is calculated, using the results of part 4 and 5:

Kd = m PA ether / m PA water = 0.4127 / 0.2458 = 1.679

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