Answer)
First, we need to find the line of regression
which is equal to
Y = a + r*(sy/sx)*X
where y is = cost
sy = standard deviation for cost
and sx is the standard deviation for square feet
mean of y = 340
mean of x 2496
sy = 58.1187
sx = 330.797
r = 0.6143468459939
Y = a + 0.6143468459939*(58.1187/330.797)*X
Y = a + 0.1079364082451*X
a = mean of y - (mean of x * 0.1079364082451)
a = 70.432
Y = 70.432 + 0.108*X
now we need to find the standard deviation for this we will calculate the predicted value of price then we will subtract the predicted value from the actual price and will take the square,
s.d = 48.64
margin of error = t*(s.d/square root of n)
n is = 10
degrees of freedom is = n-2 = 8
for df 8 and confidence level of 90
t = 1.86
margin of error(MOE) = 28.61
Now we need to find the predicted value for 2300 square feet
Y = 70.432 + 2300*0.108 = 318.832
confidence interval:
UCL = 318.832 - 28.61 = 290.22
LCL = 318.832 + 28.61 = 347.44
Suppose a government department would like to investigate the relationship between the cost of heating a home during th...
Suppose a government department would like to investigate the relationship between the cost of heating a home during the month of February in the Northeast and the home's square footage. The accompanying data set shows a random sample of 10 homes. Construct a 90% prediction interval to estimate the cost in February to heat a Northeast home that is 2,200 square feet 1 Click the icon to view the data table. Determine the upper and lower limits of the prediction...