Label 0.35 M glucose as isotonic, hypotonic, or hypertonic in comparison to 0.9% NaCl (0.15 M NaCl). Click in the answer box to display choices.
Label 0.35 M glucose as isotonic, hypotonic, or hypertonic in comparison to 0.9% NaCl (0.15 M NaCl). Click in the answer...
16.a is the saturated NaCl solution isotonic, hypertonic or hypotonic with blood? Explain. b. If a patient was administered an intravenous dose of this solution, what would happen to their red blood cells? What would be a likely initial symptom of high levels of Na* and CI? C. Read the label on the 0.9 % Sodium Chloride IV solution bag. 1. What is the osmolarity of this solution? Is this solution isotonic, hypertonic or hypotonic? Explain. 2. Is the stated...
Identify whether the following solutions are hypotonic, hypertonic or isotonic (with respect to a red blood cell). Also indicate whether crenation, hemolysis or no change will occur. a. 1.5 % NaCl b. 5 %glucose c. 0.09 % NaCl d. 3.8 %glucose e. 0.9 % glucose
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Determine if the following solutions are isotonic (0.28M in solutes), hypotonic, or hypertonic solution containing 0.28 M NaCl isotonic solution containing 0.28 M glucose isotonic solution containing 0.1 M magnesium nitrate [Mg(NO3)2] hypotonic solution containing 0.05 M KNO3 and 0.23 M glucose isotonic solution containing 0.1 M NaCl and 0.01 M CaCI2 hypotonic
When blood cells are placed in a 0.50% (m/v) solution of NaCl, this is considered: crenation isotonic hypotonic hypertonic Question 19 (4 points) Saved When blood cells are placed in a 0.9% (m/v) solution of NaCl, this is considered: isotonic hemolysis hypotonic crenation
Question 17 (5 points) Which of these solutions 0.1 m NaCl, 0.15 m glucose, 0.1 m CaCl2 would have I the lowest vapor pressure II the lowest boiling point 0.1 m CaCl2, 0.1 m CaCl2 0.15 m glucose, 0.1 m CaCl2 0.1 m CaCl2.0.15 m glucose 0.15 m glucose, 0.15 m glucose 0.1 m NaCl, 0.1 m CaCl2
What Molarity of NaCl would give a 300mOsm solution so as to be isotonic to ECF and ICF Set up and solve for X: (cross multiply) 300 mOsm X 2000 mOsmTM Try this on your own, then read on. Show work here: You should have an answer of 0.15 M. If you don't: please ask for help. You need to be able to get that calculation for the next part. Now find the number of grams per liter needed to...
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Osmosis is an ongoing process in the body that is possible because cell membranes are selectively permeable (semipermeable). Osmosis effects can be observed in the lab. For example, differences in osmotic pressure inside and outside a red blood cell can result in crenation (shriveling) or hemolysis (rupture). For this reason, care must be taken when administering intravenous (IV) fluids to hospital patients. If the IV solution has a different concentration from...