(1) The rate of effusion is indirectly proportional to the molar mass of the gas.
So in the given example, C2H6 (M.W~30 g/mol) has the highest rate.
(2) According to ideal gas law,
PV=(W/M) RT ------------(1)
Given, P=720 torr=720*0.00131579 atm=0.9474 atm.
V=2000 mL=2 L.
R=0.082057 L atm mol-1K-1
W=6.5 g
T=200 C=20+273 K=293 K.
From Eq. (1), one gets
Molar mass M=WRT/ PV=(6.5 g*0.082057 L atm mol-1K-1*293 K)/(0.9474 atm*2 L)~82.5 g/mol.
tions ecular nsity. dns o the Hg le? utial pressures mm Hg 23) which of the following zares has the highest rate...
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