21. The graph of ln A versus time for a reaction:
a. allows to determine if the reaction is exothermic
b. allows to calculate the value of the reaction rate constant
C. allows to calculate the activation energy of the reaction
d. all of the above
The relation between lnA and Actication energy Ea and rate constant k are related by Arrhenius equation as
lnk = lnA -(Ea/RT)
=> lnA = (Ea/RT) + lnk.....(1)
This follows the equation y = mx + c, so a plot of y vs x will give a straight line with slope m and intercept c.
Hence, above equation (1) while plotting lnA vs (1/T) will give a straight line with slope (Ea/R) and intercept lnk. From the slope we can calculate Ea, the activation energy of the reaction. Hence, the correct option is (C).
21. The graph of ln A versus time for a reaction: a. allows to determine if the reaction is exothermic b. allows to calc...
ln(k) = -E_a/R 1/T + ln(A) A plot of ln (k)versus 1/T result in a straight line with a slope = -E_a/R. The value of E_a can then be calculated using the value of R and to the slope of the line. This experiment uses the Arrhenius equation, which relates the temperature and specific reaction rate constant to determine the activation energy for the crystal violet reaction. The reaction will be performed at different temperatures. Once the order of reaction...
please help with #20 and 21. showing all work
20. (6pts) Consider the exothermic (left to right) reaction: 2X60) - 3Y9) +Zg) State in which direction the equilibrium will shift, if either, when each of the following happens. Explain why: a. increase in volume b. decrease in T c. increase in [X ] 21. (12prs) Sketch the curve for Energy versus Reaction Progress, on the axes provided below. On the same graph, sketch the curve for Energy versus Reaction Progress...
The following reaction was monitored as a function of time: A?B+C A plot of ln[A] versus time yields a straight line with slope ?4.5×10?3 /s . What is the value of the rate constant (k) for this reaction at this temperature?
The following graph shows the energy profile of an exothermic reaction. Based on this profile, determine the activation energy, Ea, for the reverse reaction. 100 80 60 PE (kJ) A+B 40 C+D 20 Progress of the reaction A. 20 ka OB. 100 kJ OC. 60 k) D.80 kJ
For the first-order reaction X ⟶ products, which of the following graphs is best for determining the activation energy, Ea ? Note: The best choice is the one that yields a straight line graph with the slope directly proportional to Ea . In the options below, T is the kelvin temperature and t is time. (a) k versus 1/T (b) 1 / [X] versus t (c) ln k versus T (d) ln [X] versus t (e) [X] versus t (f)...
For the reaction: C → D +B the graph of ln k vs 1/T(K) gives the equation: y = -8.1x103x + 45.0. Using this information, calculate the activation energy, (J/mol)
B) Determine the integrated rate law for this reaction.
C) Calculate the half-life for this reaction.
D) How much time is required for the concentration of A to
decrease to 4.25x10^-3 M
A certain reaction has the following general form: At a particular temperature and Alo 3.40 × 10-2 M concentration versus time data were collected for this reaction, and a plot of ln A versus time resulted in a straight line with a slope value of -2.91 x 10-2...
2. Draw a labeled reaction-energy diagram (graph of potential energy versus reaction coordinate) for a three-step overall exothermic reaction with the A. first step being the rate-determining step B. third step being the rate-determining step Label each graph with the following: reactants (r), transition states (ts.), intermediates (int.), products (p). activation energies (Ea), and overall standard heat of reaction (AH). (Note: Each subscript, x, needs to be a number that refers to the appropriate primary mechanistic step. For example, Ea,...
2. Draw the following the energy diagrams: a. exothermic reaction with small activation energy b. endothermic reaction with large activation energy c. exothermic reaction with large activation energy d. endothermic reaction with small activation energy
The following reaction was monitored as a function of time: A→B+C A plot of ln[A] versus time yields a straight line with slope −4.5×10−3 /s . If the initial concentration of A is 0.240 M , what is the concentration after 240 s ?