16)
Moles of Cr = Mass/Molar mass = 0.7655/51.996 = 0.014722
Moles of Cl = 1.566/35.453 = 0.044171
Simplest mole ratio i.e. diving each moles with smallest number (0.014722)
Cr : Cl = (0.014722/0.014722) : (0.044171/0.014722)
Cr : Cl = 1 : 3
Thus, empirical formula is Cr1Cl3 = CrCl3 ....Answer
17)
Limiting Reagent - running out first
18)
Yield of reaction
19)
A = € b C and Beer's law
20)
M1 * V1 = M2 * V2
M1 * 25 = 0.1250 * 32.36
M1 = 0.1618 mol/L ....Answer
Let me know if any doubts/answer is not matching.
15. Use the Ideal Gas Law and the answers to questions 12, 13 and 14 to calculate the number of moles of hydrogen g...
16. A student reacted 0.7655 g of chromium (at. wt = 51.996 g/mol) with exactly 1.566 g of chlorine (at. wt. -- 35.453 g/mol). Convert both these masses to moles and determine the empirical formula (like A,X,) of the compound of Cr and CI. SHOW YOUR WORK 17. In a chemical reaction, the substance which gets used up first (or runs out first) is called the _(write in the correct words). 18. In a chemical reaction, the maximum amount of...
16 A student reacted 0.7655 g of chromium (at. wt 51.996 g/mol) with exactly 1.566 chlorine (at. wt.-35.453 g/mol). Convert both these masses to moles and determine the empirical formula (like A x) of the compound of Cr and CL. SHOW YOUR WORK gof 17. In a chemical reaction, the substance which gets used up first (or runs out first) is called the (write in the correct words). 18. In a chemical reaction, the maximum amount of product which can...
BG20.2 Determination of the Ideal Gas Law Constant Page 9 of 12 PRELAB QUESTIONS (Show all calculations.) I. Write a balanced chemical equation for the reaction of magnesium with hydrochloric acid. 2. A class ran this lab as described above. One student cut a piece of magnesium ribbon and found that it weighed 0.0347 g. The magnesium reacted with the 4.0 mL of concentrated hydrochloric acid. The concentration of concentrated hydrochloric acid is 12 mol/liter. Which reactant is the limiting...