Question

Two cables support a 30.0 kg sign, as shown, where one cable extends horizontally to the wall and the other makes an angle of 40.0° with the ceiling. The tension in the horizontal cable is equal to 40° a. 597 N b. 457 N с. 350 N d. 294 N 30 kg e. 247 N which pivots at its center. A child of mass 25.C

refer to pic

Answer 1

Drauwing the problem the ven scenario T2 Tisina (a-omk) tsuapendid m-30 K Waght= W=mg Ascumt ng the tenatanu in the cable au cable (u6) T Tension in tlr inclihed T2 Tenston in ttu horzpntal cable >) verhical Cable Lthe cable which iu thu sign (m Tenston in ths Weghtfsign= A ovicud in the questbn that the cables are $gn, then the mbtron thuxe wouldn't be to thu 3

supendid that the sign assum SO, accelerationf san = A = 0 m/s2 net Hena second lau f mottan (Newton's to the'M' ayng yextiCal Fnetm(a) Ts- W =m(0) = o N Ts= Wmg

Now, in fee CA0C) angu at 96180 Sum = 186-qd- = 180°- q0°-400 Qaderd verticalhegontai T into Companent a axuas shocon) Ticoso Cetong verhical1 horigantal) Ti sin o al the Sina the supported, then whole iancng foras oould be e Cuch Gther . So. balan ang the forcesround O berigontal vetcal duection Ti cos T3 vexticat (from D th forcu alang hovizontal Tisina T2 fam) ma Sino 2 CoSox T mgtanc

30x9-8 tan50 N T2=3s0 N in the hogsntal cable u Te= 350 N Hena, the tenuien 350 N CoTTect answer.