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5-10 The data below refer to the following reaction: 2NO(g) + Brz(g) 2NOBr(g) [NO] 2.5 [Brz] Concentration (M) Initial...
A student ran the following reaction in the laboratory at 225 K: 2NOBr(g) 2 2NO(g) + Brz(g) When she introduced 0.198 moles of NOBr(g) into a 1.00 liter container, she found the equilibrium concentration of Br2(g) to be 1.89x10-2 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
The equilibrium constant, Kc, for the following reaction is 5.19×10-3 at 286 K. 2NOBr(g) <-->2NO(g) + Br2(g) Calculate Kc at this temperature for the following reaction: NO(g) + 1/2Br2(g) <-->NOBr(g) Kc=?
The equilibrium constant, Kc, for the following reaction is 7.68×10-3 at 307 K. 2NOBr(g) 2NO(g) + Br2(g) Calculate Kc at this temperature for the following reaction: NO(g) + 1/2Br2(g) NOBr(g)
The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) 2NO(g) + Br2(g) If an equilibrium mixture of the three gases in a 11.1 L container at 298K contains 0.376 mol of NOBr(g) and 0.396 mol of NO, the equilibrium concentration of Br2
Consider the following reaction where Kc = 154 at 298 K: 2NO(g) + Br2(g) 2NOBr(g) A reaction mixture was found to contain 2.42×10-2 moles of NO(g), 4.38×10-2 moles of Br2(g) and 9.68×10-2 moles of NOBr(g), in a 1.00 Liter container. Indicate True (T) or False (F) for each of the following: 1. In order to reach equilibrium NOBr(g) must be produced. 2. In order to reach equilibrium Kc must decrease. 3. In order to reach equilibrium NO must be produced....
A student ran the following reaction in the laboratory at 254 K: 2NO(g) + Br2(g) ⇌ 2NOBr(g) When she introduced 0.185 moles of NO(g) and 0.130 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.152 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc =
A student ran the following reaction in the laboratory at 295 K: 2NO(g) + Br2(g) <---> 2NOBr(g) When she introduced 0.153 moles of NO(g) and 0.123 moles of Br2(g) into a 1.00 liter container, she found the equilibrium concentration of NOBr(g) to be 0.117 M. Calculate the equilibrium constant, Kc, she obtained for this reaction. Kc = ____ The equilibrium constant, Kc, for the following reaction is 6.50×10-3 at 298K. 2NOBr(g) <---> 2NO(g) + Br2(g) If an equilibrium mixture of...
The following reaction has an equilbrium constant Kc =3.07e-4 at 24oC. 2NOBr(g) <---> 2NO(g) + Br2(g) Decide whether the reaction mixture is at equilibrium, given the conditions below, or if the reaction will go left or right to achieve equilibrium. Type left, right or equilibrium. [NOBr] = 0.103 M [NO] = 0.0134 M [Br2] = 0.0181 M
Consider the following reaction where Kc = 154 at 298 K. 2NO(g) + Br2(g) 2NOBr(g) A reaction mixture was found to contain 4.44×10-2 moles of NO(g), 3.68×10-2 moles of Br2(g) and 7.92×10-2 moles of NOBr(g), in a 1.00 liter container. Is the reaction at equilibrium? If not, what direction must it run in order to reach equilibrium? The reaction quotient, Qc, equals . The reaction A. must run in the forward direction to reach equilibrium. B. must run in the...
The equilibrium constant, Kc, for the following reaction is 6.50X10-3 at 298K. 2NOBr(g) =2NO(g) + Bra(g) If an equilibrium mixture of the three gases in a 11.0 L container at 298K contains 0.270 mol of NOBr(g) and 0.214 mol of NO, the equilibrium concentration of Bra is M. Submit Answer Retry Entire Group 6 more group attempts remaining