How many grams of NaCl would be needed to prepare 23.11 L of a 1.12 M NaCl solution?

Question

Question

Answer 1

Answer #1

molarity = number of moles of NaCl / volume of solution in L

1.12 = number of moles of NaCl / 23.11

number of moles of NaCl = 1.12 * 23.11 = 25.9 mole

number of moles of NaCl = mass of NaCl / molar mass of NaCl

25.9 mole = mass of NaCl / 58.44 g/mol

mass of NaCl = 1514 g

Therefore, the mass of NaCl = 1514 g

Answer 2

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