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The enthalpy change for the reaction of hydrogengas with bromide to produce hydrogen bromide is 68.2kJ for the quation a...

The enthalpy change for the reaction of hydrogengas with bromide to produce hydrogen bromide is 68.2kJ for the quation as written

H2(g)+Br2(l)=2HBr(g)

delta H=-68.2kJ

What is the enthalpy change per mole of hydrogen bromide produced

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Answer #1

H2!8)+ Brz (6) → 2HBrey) TH=-6802 kJ By rren, Enthalphy change for 2 mol H Br=-68.2 kJ o Enthalpy change for I mole HBr = -68

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