1)
At equilibrium:
Co(OH)2 <----> Co2+ + 2 OH-
s 2s
Ksp = [Co2+][OH-]^2
2.9*10^-16=(s)*(2s)^2
2.9*10^-16= 4(s)^3
s = 4.17*10^-6 M
Answer: 4.17*10^-6 M
2)
[OH-] = 2s
=2*4.17*10^-6 M
= 8.34*10^-6 M
use:
pOH = -log [OH-]
= -log (8.34*10^-6)
= 5.0788
use:
PH = 14 - pOH
= 14 - 5.0788
= 8.9212
Answer: 8.92
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