Question

51. A large pharmaceutical company with distribution centres in Canada and the United States has its call centre located in Mississauga, Ontario. There are 20 customer service representatives answering calls from 8 a.m to 9 p.m. through the week, and from 9 am. to 5 p.m. on Saturdays. The call centre reported the number of calls waiting to be answered between the hours of 9 a.m. and 10 am over a 50-day period as shown below. Sum marize the data in a chart, and interpret. 47 1 8 46 76 26 4 3 39 45 4 21 80 63 100 65 91 29 7 15 7 52 87 39 106 25 55 2 3 8 14 38 59 33 76 71 37 51 1 24 35 86 185 13 7 43 36 20 79 9

Answer 1

Solution: A large pharmaceutical company with distribution centers In Canada and the United States has is call center located in Mississauga. Ontario. There are 20 customer service representatives answering calls from 8 an to 9 p.m. through the week and from 9 a m. to 5 p.m. on Saturdays. The call center reported the number of calls waiting to be answered between the hours of 9 an and 10 am. over a 50-day period as shown below.

Summary of the data:

x<-c(47, 1, 8, 46, 76, 26, 4, 3, 39, 45, 4, 21, 80, 63, 160, 65, 91, 29, 7, 15, 7, 52, 87, 39, 106, 25, 55, 2, 3, 8, 14, 38, 59, 33, 76, 71, 37, 51, 1, 24, 35, 86, 185, 13, 7, 43, 36, 20, 79, 9)

summary(x)

Min. 1st Qu. Median Mean 3rd Qu. Max.
1.00 10.00 36.50 42.62 62.00 185.00

So, the mean of the number of waiting calls is = 42.62.

The median of the number of waiting calls is = 36.50.

The minimum of the number of waiting calls is = 1.

The maximum of the number of waiting calls is = 185.

Also, First Quartile = 10 and Third Quartile = 62.

The Histogram of the data plotted below:

Histogram of x LO 0 50 100 150 200 X Frequency

The histogram suggests the data is skewed right. That is why the mean is greater than the median.

The Barplot of the given data on 50 days:

00 00 09 0