Question

Method

Null hypothesis H₀: All means are equal Alternative hypothesis H₁: At least one mean is different

Equal variances were assumed for the analysis.

Factor Information

Factor Levels Values StressLevel 3 High, Low, Medium

Analysis of Variance

Source DF Adj SS Adj MS F-Value P-Value StressLevel 2 261.361 130.681 18.76 <0.0001 Error 69 480.583 6.965 Total 71 741.944

Model Summary

S R-sq R-sq(adj) R-sq(pred) 2.63912 35.23% 33.35% 29.47%

Means

StressLevel N Mean StDev 95% CI High 24 5.2083 2.6536 (4.1336, 6.2830) Low 24 9.8750 2.7077 (8.8003, 10.9497) Medium 24 7.5000 2.5538 (6.4253, 8.5747)

Pooled StDev = 2.63912

For this assignment, use data from W1 Project.

This week, you will explore the hypothesis that recall will vary as a function of stress levels.

Conduct an ANOVA comparing participants' Recall1 across all three stress-level conditions (low, medium, and high).

Conduct post hoc tests if needed, using the Tukey method.

Move your output into a 1- 2-page Microsoft Word document and write a short, APA-formatted interpretation of the results.

Answer 1

Sol:

Consider Null and Alternative hypothesis Null hypothesis, H all m eans are equal A lternative hypothesis, H: at least one mean is different A ssume that the level ofsignificance is 0.05 From the A NOVA output, observe that the p-value is 0.0001 Compare thep-value with the level of significance Here, the p-value is lesser than the level of significance then reject the Null hypothesis Hence conclude that at least one mean is different Compare the individual differences From the Tukey's method, observe that the 95% differences does not contain zero value. Therefore, three individual differences are different confidence interval for th ree individual