Homework Answers
As container is insulted
Heat loss by gold = heat gained by water
ΔH1= ΔH2
ΔH = m*c*ΔT
Where m= mass, c = specific heat capacity ΔT = temperature change
Note : specific heat capacity of water = 4.186J/gC
Specific heat capacity of gold = 0.129J/gC
Now, 0.129* 31.2g*(69.5-T) = 4.186*63.6g*(T-26.9)
279.7 - 4.02T =266.23T -7161.58
270.25T = 7441.276
T= 27.53 C
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