Question

2. If you prepared a 0.15 M CH.COH - 0.15 M CHCO Na buffer, would you expect the resulting buffer capacity to be higher, lowe


c. Measure the pH of the Beaker #2 solution, via a pH meter, and record in data sheet. Part II: Dilute Buffer Solution In thi
Part I: Drute unter Volume CH.CO.H. ml. Molarity CH.CO:H, mole/L Beaker 10.0 mL 0.50 M Beaker 2 10.0 mL 0.50 M Moles CH3COH B
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Answer #1

If you prepared a 0.15 M CH3COOH - 0.15 M CH3CO2Na buffer, the resulting buffer capacity would be expected to be the same as the buffer you prepared in Part II of this lab.

Explanation:

In Part II of this lab, moles of CH3COOH = 0.5 mol/L * (10/1000) L = 0.005 mol

And moles of CH3COONa = 0.5 mol/L * (10/1000) L = 0.005 mol

Now, pH = pKa + Log([CH3COONa]/[CH3COOH])

i.e. pH = 4.74 + Log(0.005/0.005)

i.e. pH = 4.74

The given buffer does also have the same pH. Hence, they have the same buffer capacity.

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