Let i* for project 1 be r. Then
1,000 = [2,100 / (1 + r)] - [820 / (1 + r)2]
If (1 + r) = R,
1,000 = (2,100 / R) - (820 / R2)
1,000R2 = 2,100R - 820
50R2 = 105R - 41 [dividing by 20]
50R2 - 105R + 41 = 0
Solving this quadratic equation using online solver,
R = 1.582 and R = 0.52
When R = 1.582,
1 + r = 1.582
r = 0.582 = 58.2%
When R = 0.52,
1 + r = 0.52
r = - 0.48 = - 48%
So (A) there is a unique positive i* of 58.2%.
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