Question

List of keywords in Python can be obtained with the statements

import keyword

kw = keyword.kwlist

Use list comprehension to print out a lower case sorted 2-column list. The output should look as follows:

and as assert async await break class continue def del elif else false except finally for from global if import in is lambda none nonlocal not or pass raise return try true while with yield

Answer 1

Please find the program below:

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import keyword
kw=keyword.kwlist
#converting all strings to lower case and assigning to ks
ks=[x.lower()for x in kw]
#sorting the list
ks.sort()
i=0
while i<len(ks)-1:
print('{:<20} {:<20}'.format(ks[i],ks[i+1]))
i=i+2
print(ks[len(ks)-1])

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keywords.py - D:/Python_Scripts/keywords.py (3.7.3) Eile Edit Format Run Options Window Help import keyword kw-keyword.kwlist #converting all strings to lower case and assigning to ks ks x.lower ()for x in kw] #sorting the list ks.sort i-0 while i<len (ks)-1: print ('{:<20 {:<20}'.format (ks [i],ks [i+1])) i-i+2 print (ks [len (ks) -1] Ln: 11 Col: 20 ====== RESTART: D:/Python Scripts/keywords.py ======== ===== and as assert async break await continue class def del elif else false except finally for from global import is if in lambda none nonlocal not or pass raise return true try with while yield >>> Ln: 29 Col: 4