Determine the minimum dissolved oxygen (DO) concentration in a river downstream from a wastewater treatment plant (W...
A wastewater discharge has a flow equal to upstream flow of the river it is being discharged into. The river upstream has a DO of 7 mg/L, and negligible BOD. The wastewater discharge has an ultimate BOD of 50 mg/L, and negligible DO. It is determined that it would cost an equal amount of money to reduce the BOD to 25 mg/L or to increase the DO to 8 mg/L. Which alternative, considering DO sag, would you judge to be...
A community wastewater treatment plant has an average discharge flow rate of 3.5 MGD (million gal per day) with a BOD5 concentration of 28 mg/L. The stream receiving the discharge has a flow rate of 12 ft3 /s and a BOD5 of 11 mg/L. You may assume k = 0.18 d -1 . a. Determine the BOD5 immediately after the streams have mixed. b. Determine the BODu for the stream after the streams have mixed. c. Downstream of the discharge...
Please answer #5 4. What is the theoretical oxygen demand for a wastewater flow of 25 MGD (million gallons per day) containing 100 mg/L ethanol (C2H5OH)? 5. If this wastewater was discharged into a stream flowing at 10 m/s with an ultimate BOD of 5 mg/L, dissolved oxygen (DO) of 5mg/L, and deoxygenation rate coefficient ka of 0.2/day: (a) Find ultimate BOD of mixture just downstream of wastewater discharge. State all assumptions used. (b) In your opinion, is the wastewater...
is proposed to discharge a wastewater to a small river (wastewater and river characteristics given below). The temperature of the river and wastewater i and velocity downstream of the discharge is 1.5 m/s. Saturation DO concentr:a 25°C is 8.2 mg/L 2. It s 25°C, Wastewater 1.5 w 31.5 6.1 River Parameter Flow (m/s) BODu( mg/L) DO (mg/L) negligible 8.0 kra20c 0.41 day kd@20c = 0.26 day. Determine: a. Ultimate BOD just downstream of the point of discharge (8 pts) b....
QUESTION 3 a) After a point of wastewater discharge, the dissolved oxygen (DO) concentration is found as 83.33% of the saturation DO. The remaining BOD after 5 days at the point of discharge is 10.13 mg/L. The BOD rate constant determined in the laboratory under standard conditions is 0.115/day. The saturation DO concentration in the river water is 9 mg/L. The deoxygenation and the reaeration rate coefficients are 0.25/day and 0.45/day, respectively. The river travels at a velocity of 0.12...
The East Hartford WWTP discharges 150 MGD of treated wastewater into the CT river. The treated was tested in the lab and found to have aBOD5 of 17.5 mg/L and an ultimate BOD (Lo) of 92 mg/L at 20oC. Find the reaction rate K, for the treated wastewater. The CT river has a flow of 250 m2/s and an ultimate BOD (Lo) of 6 mg/L. the DO of the river is 4.5 mg/L and the DO of the wastewater is0.2...
O The town of Gangnam in Seoul, Korea discharges 17360 m3/day of treated wastewater in the Han River. The treated wastewater has a BOD5 of 12 mg/L and a BOD decay constant, k, of 0.12 day at 20 °C. The river has a flow rate of 0.43 m/s and an ultimate BOD, Lo, of 5 mg/L. The DO of the river is 6.5 mg/L and the D0 of the wastewater is 1.0 mg/L (a) Calculate the ultimate BOD of the...
DO Sag Curve: A wWTP discharges wastewater to a nearby river and a city 2.88 km downstream uses the river for water supply. Data is given below. Determine the DO at the intake of the city. Paraneter Flow (m3/s) BODL (mg/L) Da (mg/L) River (after mixing) 0.3 43-4 Speed (m/s) Ka at 18°C(d-) Kr at 18° C (d-) Answer: t- 0.333 d, D0-o mg/L (cannot be a negative number) 18 0.1 1.83 2.03
e3 (20) LEMery has asked you to assist them in preparations to file for a NPDES germit toad discharge wastewater into t Rive r is 5 mg/L of DO. They have asked you the following questions: What is the cr where (at what distance) he Zmellsbad River. The DNR water quality criterion for the downstream does it occur? Is ther d oxygen? They have provided you with the following data. They pertaitn a problem with the cinicau and following data....
38 w Jersey requires that engineering design of water, storm, wastewater and air systens be colabor because within the space of 800 square miles, live about 3 milion people. This means each person can affect the ar 4u and water resources of another person. To add to the complexity of overlapping resource demands is the institutional complexity of independent municipal jurisdictions. There are over 150 separate municipal sewer and water utilities a separately elected munioipal council and mayor. Therefore, because...