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Exercise about two-dimensional random variables, independence and covariation:

Suppose, two-dimensional random variable (X, Y) has probability density function as follows: 0y1 + f(x, y) 2xy) ,0 <x<1, othe

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Answer #1

x y, 404 0くえく0<4く 2y We kuow 1 2 + 2 [R). 3 t 2 C 4Fta /s PRA naln 2 L 2 t e)dx (a) -56/s 1e), oくuくI Now Marginal P + 2 y - I 3,nendant (x)F( ( kepandead Hente) メqリ are Toint 3 0くれく) E () E (y2) l+2 t3 2 ut2) t3 し +2 t3 t2 t At 2 at2,o ats2 1 sut2 At2 t 3 E (M E (x) 2 2 + 2 +n 2 Ne $/2 E L) (주를 (3 X 22 (우. 들 주, 두) 대 /5 20 * 2 x t 27/1 13/30 Now Hence E (xy)-EC E) cov 5/270 3 3 x103 E (x2) Var lx) Ex) 2 27/50 04 7 Varl9)E2 - ) 2 30 - 073 3 Hewee Conelalion

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