An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent of H2 over a palladium catalyst to give hydrocarbon B. Hydrocarbon A also reacts with OsO4 to give diol C. Upon reaction with ozone, followed by zinc treatment, hydrocarbon A yields ketone D and aldehyde E, C2H4O.
The unknown hydrocaron A
i) has a formula C6H12, typical for a alkene
i) it reacts with one mole of H2 means it has one reducible bond
ii) it reacts with OsO4 with to give diol means the reducible bond is C=C
iii) upon ozonlysis it gives one aldehyde (C2H4O, acetaldehyde) and ketone. overall transformation in this reaction is C=C to 2 x C=O. Since acetaldehyde is one of the products the unknown compound A is 2-alkene. Since other product is ketone it has substittent on 3rd carbon.
From the above discussion the strctures of A, B, C, D and E are as follows
An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent of H2 over a palladium catalyst to give h...
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