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An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent of H2 over a palladium catalyst to give h...

An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent of H2 over a palladium catalyst to give hydrocarbon B. Hydrocarbon A also reacts with OsO4 to give diol C. Upon reaction with ozone, followed by zinc treatment, hydrocarbon A yields ketone D and aldehyde E, C2H4O.

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Answer #2

The unknown hydrocaron A

i) has a formula C6H12, typical for a alkene

i) it reacts with one mole of H2 means it has one reducible bond

ii) it reacts with OsO4 with to give diol means the reducible bond is C=C

iii) upon ozonlysis it gives one aldehyde (C2H4O, acetaldehyde) and ketone. overall transformation in this reaction is C=C to 2 x C=O. Since acetaldehyde is one of the products the unknown compound A is 2-alkene. Since other product is ketone it has substittent on 3rd carbon.

From the above discussion the strctures of A, B, C, D and E are as follows

OH OH

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