Question

A 1300 kg steel beam is supported by two ropes. What is the tension in each?

rope 1?

rope 2?

Answer 1

The following figure shows the free body diagram of the steel beam supported by the two ropes cos20 7, cos30° Rope I Rope 2 T. T, sin29 T2 sin30° In the above figure mg is the weight of the beam, Ti and T2 are the tensions in rope 1 and 2 respectively Apply equilibrium of forces along the vertical direction. T cos 20° + T2 cos 30°-mg = 0 T cos 20° + T2 cos 30° = mg cos 20°1T, cos 30°-(1300 kg)(9.8 m/s* 11 cos 20° T2 cos 30° 12740 N Apply equilibrium of forces along the horizontal direction. T sin 30°-T sin 200 Sin 300684(7) Replace T, with 0.684 (T) in equation (1) and solve for T T cos 20。4(0.684 (n) cos 30° = 12740 N (1.532)-12740 N 7-8315.6N Now, substitute 8315.6 N forT, i T2-0.684(83 15.6 N)-5688 N n T 0.684(7)