Question

334 CH bond length ) Rank Lewiym 1.9 84 The orbital diagram that follows shows the valence elec trons for a 2+ ion of an clement. (a) What is the element! (b) What is the electron condiguration of an atom of this ele ment Section 82] lect orbitale? Which have as core ! 8.13 Write the Lewis symbol for atoms of each of the food ments (a) AL(b) B. (c) Ar. (d) Sr. 8.14 What is the Lewis symbolisch the following Ful in these lop in 8.15 (a) H-0 Nm0 0 N=0 The partial Lawis structure that follows is for a hydrocarbon molecule. In the full Lewis structure, each carbon atomutis fies the octet rule and there are no unshared electron pairs in the molecule. The carbon-carbon bonds are labeled 1.2 and 3. (a) How many hydrogen atoms are in the molecule? (b) Rank the carbon-carbon bonds in order of increasing of the ferr o loses electrons in the 8.17 Predict the chemical form of the loco between the following pairs of elements: and S. c) Y and . (d) Mg and N.

Answer 1

8.4. Ans :-

In the diagram 4d-orbital have 6 electrons out of which only first orbital is completely filled i.e. 2 electrons, others orbitals are singly filled.

(a). The given element must belong to d-block because it has partially filled d-orbitals i.e. 4d⁶-electrons. Since, 2 electrons are removed therefore element must have two electrons less than the atomic number and this atom must have 5s-orbital outer most shell. Therefore, Group number of the element must be 6+2= 8^th group and period number of the element must be 5^th.

Hence, the element will be Ruthenium having symbol " Ru ".

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(b). The electronic configuration of the atom Ru (Z=4) is according to increasing order of energy of the orbitals is : 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s¹4d⁷.

and

Noble gas electronic configuration is = [Kr] 4d⁷ 5s¹