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- -/10 points Thermo: Calorimetry - ice + steam 0/6 Submissions Used My Ne 0.1 kg of steam at 100°C is added to 0.41 kg of ic
8. -70 points Specific Heats & Latent Heats 070 Submissions Used These values will be needed for the following calorimetry pr
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Answer #1

let the final temperature of the mixture is T

heat lost by steam = heat lost by ice

0.10 * 2240 + 0.10 * 4186 * (100 - T) = 0.41 * 334 + 0.41 * 4186 * (T - 0)

solving for T

T = 19.6 degree C

the temperature of the mixture is 19.6 degree C

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