Question

I just want to double check my work for Q1, 2, 3 in the blank spaces and the Nernst equations.

Concentration Cells 1) Concentration cell #1 : Which solution is being reduced, the IM Cu2 or the 0.001M Cu? VE 90 What was the measured cell potential for the 1M Cu/0.001 M Cu concentration cell? 14,S mV Measured Ecel= Use the Nernst equation to calculate the expected cell potential for the 1M Cu/0.001M Cu concentration cell; refer to the experimental directions. Show your work. Calculated Ecell 2) Concentration cell #2: What was the measured cell potential for your concentration cell after you added 6M NH3 to the 0.00IM Cu? Measured Ecell= Enter your measured cell potential in the Nernst equation and calculate the concentration of Cu in the vial after you added the ammonia. Show your work PN Calculated [Cu= 977S 3) Concentration cell #3: Unknown #: What was the measured cell potential for your IM Cu/Unknown E concentration cell? 29.6 m Measured Ecell Enter your measured cell potential in the Nernst equation and calculate the concentration of your Unknown E. Show your work. Cu Calculated [Cu2in Unknown E=

Answer 1

Concentatiuna M Cu2t 0.001 M Cu2+ elechrondone acceped by beny ou_Cun, Soluhion uducee - .001M Cųlt 0.0S31 Cu2t o.001M Log. 6. 059 O.001 M -0.0S9 x (-3) 0.o88 65 V 88.6 mV 2) ammonia Solufium ip 6m added chamged.(ut r uncentratm noLo Cell potent'al measwed 0.O59 Eeet Cult 1m)

0.0S91 TM O. 4-69 X2 O.OS9 amtilog -15.871) 1.35X10 M Soj Canunhratun 0.001MCu -16 M. chget umbnalum 29.6 mV MCultcaltakoa) taty) m 0.OS9 -0.059 29 6X10 V 2 og -1Do17 10-(10012). O. O99 M mjcno 0.093M