Question

Why have i done wrong?

I got 0 to 0.45 to 0.1 to 1.3 to 0.95 and back to 0

Please show the answer in KN*m in the graph with all the number.

800 N 600 N 1200 N m 1 m 1 m 1m 1m appear correct VISually Decause tne ines overiap, Dut tne system will marK IT wrong reset ?help add vertical line off delete segment change segment 800 N 600 N 1200 N m 1 m 1 m 1 m 1 m M (kN-m) 1.50 linean decreasing slope 1.3 1.00+ 0.95 inear decreasing slope 0.500.45 (m) 0.1 -0.50+ -1.00 -1.50 Previous Answers Request Answer Submit Incorrect; Try Again; 5 attempts remaining

Answer 1

400 N 600 N 1-2KMM Ape ABy EA Since beam is Ay in static equil: bdum A 20 2Rj 2 0 - 600 x 10x 3-Goo Xix AytBy-40700 AstBy -l20 (4-a0 N 9-9s KN . By By 2 950M Azao AS 2 450 N

Bending Momeuit dieega curm Part secti on A C * Ay2 460 N Meoc-4.46 Xx 20 1m 2) Mci) 2 0.45 at x 20.48 kN Mixa0.4H YKMM KMm Part 4ecton co CJust LHs of 0.4-KM palut Jmexy Mol 0-46 +03 (K-t)20 Cx-0m 0SKN mcx) 2 0 46 o o.46-1 Or8-9.3x KMm ext xel m MC) 0.4り kmm mca)a D.3 -0.35 x 2 O kNm CJust LHs t poiut D (Just Rts of pauct at xiam s Section DR Purt - 9.6KN mUR-o.46 X T. -1- O Coceay O.46 kN +0-8 FPAR COSIT at x2 2 m 2) Mox) 2-D,35x t9-0 a.36x1t2 LSust RHs of KMm Mcay 2 +13 kMm 0.36X 3 +2. at a 3 m 2 2. me3) +a-5 kMm ,KN C Just LHs ot d,6 kN (+9kMm Part sectiom BA+ 0.48KN

.KT8 0.6x t1.3 mcx)2 0.4ちx +3-9KMM ーて 0.95 KMm mc3) -0-95x3 +3.名 at oc 2 3 m 2 C Just RHs of 6 -0,95メ4+3.8 20kMm

6.3 N A (9 kMm skv 0.48 kN O-gys k N VCRM)O.KN A o.35 KN O95KN .3KMM Mekwm) BuD O.95KNM 0.45 KMm (t 50 as shauon in 2thrre is mo wtiong in &while giving answer fngat B.M 0 But you may hawe done misteki ruising ohile auline Passible mistake is ste you aay might ahile ruwing-e we diffleene buttons use + add vertical tine oe futton POKCC ble possible futtony to as mex) auve use Arfe