Question

c. 0.100 M AICI: 25. How many moles of KCl are contained in each solution? MISSED THIS? Read Section 5.2; Watch KCV 5.2, IWE 5.2 a. 0.556 L of a 2.3 M KCl solution b. 1.8 L of a 0.85 M KCl solution c. 114 mL of a 1.85 M KCl solution What react v 35. What produ

Answer 1

Since molarity and volume are given, we can calculate number of moles of solute [KCl] present in the solution

using the relation number of moles of solute present = molarity of solution *volume of solution in liters
[Note: remember to convert ml in to Liters before doing calculation !]

A)
volume = 0.556 L
molarity = 2.3 M

Therefore number of moles of KCl present = volume *molarity
= 0.556 L*2.3 M = 1.2788 mols
********

B) volume = 1.8 L
molarity = 0.85 M

Therefore number of moles of KCl present = volume *molarity
= 1.8 L *0.85 M= 1.53 mols
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C) volume =114 ml= 0.114 L
molarity = 1.85 M

Therefore number of moles of KCl present = volume *molarity
= 0.114 L *1.85 =0.2109 mols
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thanks !