Question

Question 1 1 pts A 1.50L glass flask contains Ar gas at a pressure of 745 torr. Nitrogen (N2) gas is added to this container and the pressure was measured to be 875 torr. What is now the partial pressure of N2 gas in this container? Use this information to answer Q2-5. Flask A is a 1.50 L glass flask containing Ar gas at a pressure of 652 torr. Flask B is a 2.50 L glass flask containing He gas at a pressure of 822 torr. These 2 flasks are connected by a valve to each other. which was initially closed when the original pressures were measured. The valve between the 2 flasks is opened. There is no temperature change to the flasks when the gases are mixed. 1 pts Question 2 When the valve is opened between flask A and B, select the statement below that best explains the gas pressures in flasks A and B The gas pressure in A is greater than the gas pressure in B The gas pressure in A is equal to the gas pressure in B The gas pressure in A is less than the gas pressure in B

Answer 1

145 Wednesday NOVEMBER Wk 487333-032 15 16 17 18 19 2 29 30 31 2017 01 445 torr total P = 875 torr NO after Total & 1. 51 flask Ar at addition of Na gaste Pressure & Part PN 875 = 745 + PN- 130 torr А TSL B 250L He 822 torr 652 torr temp are to After value is opened, since there is no change to the flask when the gases mixed tell the gas in A becomes equal the gas pressure in B. the option B After the we value is open, know from gases starts Graham's Law diffusing and rate & Diffusion Me 652 14 822 J 40

DECEMBER 3 5 1 17 18 19 20 21 22 30 31 10 24 Thursday NOVEMBER 2017 /W48 0.25 'He No. of moles Mar = 1.5 L x 652 torr RT The = 2.5 X 822 RT Total moles ng a MAr thre. = (1.5X652 t 2.5X822) = 3033 RT Mole fraction = MAY - -0.322 1.5 x 652 11.5x 652 t 2.5% rupe - ҮНа MT toor 2.5 X 822 (1.5x652 +251822) = 0.677 Partial Pressure PAr = KA. Pg Pre= x He Py. Q =/0.322 x 7585) ou Pre - 0.677 x 758.25 2244.45 Tire = 513.33 tory QS After the value is opened the gases start diffusing until the pen both flask becomes quel to ABX Aory 1758.251 = ( 822 X 2.5) + (652X1.5) - 758.25 tors 14-0)