ICE Table:
Given at equilibrium,
[COBr2] = 0.233
+1x = 0.233
x = 0.233
Equilibrium constant expression is
Kc = [COBr2]/[CO][Br2]
Kc = (+1x)/(0.5-1x)(0.4-1x)
Kc = (+1*0.233)/(0.5-1*0.233)(0.4-1*0.233)
Kc = 5.23
Answer: A
26. A mixture 0.500 mole of carbon monoxide and 0.400 mole of bromine was placed into a rigid 1.00-L container and...
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