Question

Complete and balance the following redox reaction in basic solution MnO4-(aq) + Br-(aq) → MnO2(s) + BrO3-(aq) Attempts remaining: 3 Complete and balance the following redox reaction in basic solution 103-(aq) + Re(s) → Re04 (aq) + 10-(aq) Attempts remaining: 3

Answer 1

solution mnou caa) + Bocan, MnO2 (s) + Broj cas (Basic) Step- I . The skeletal ionic equation is : mnot cas, + Bocan, MnO2 (s) + B2O3(99) Step II Assign oxidation No. of for mn, Br +4 +7 - cag) mino + Br → minois) & Brog (ag) Step-II calculate the increase and decrease oxidation no. and make them equal. 2 mnoücadis + B = -satnog oss + Bozcaq) ne Reaction occurs in the basic medium and further the ionic charges are not equal on both the sides, add 2014 on the Right to make ionic charge equal a mnoç can + Bocan a MnO2 (s) + Brog cay + 2014 Step I finally count the Hydrogen atoms, and add Appropriate. no. of water modecule (i.e Ho on the left to achieve balanced Redox Reca change.. a mnou cags + Br can + How a mno(s) #Brog cao +2014 (99)

can + Reis) > Reou cay + Io (aq) (Basic) I solution Step-I the skeletal ionic equation is 403(aq) + Reis -> Re°4 can't I ocaq) Step- Assign oxidation Namber for Igre +5 3 Reon can, & 1o cua). Step-II calculate the increase and Decreases oxidation number and make them eqrial, IO. cad) +5 (a ) 7 Io Canto 4 Reis 4 Reon + Z Io cao) ( Step- As the reaction occusks in the Bagic medium and for the the ionic charges are not equal on both the sides, Add 40H on the left to make ionic charge equal. 9) 7 Io + 4 Re+40172 4 ReO4 + 750,00 (aa) (5) step-I Finally count the Hydrogen atoms, and add APPropriate Number of water molecule (le 2H₂O) on the Right to achieve balanced Redox change. 7 Io Cant are + 404 can) (s) (aq) 4 Reo &710 + 2 H2 (4) 49 (49