Question 4 1 pts Given the following reactions, (1) 2PCl3g) 2Pg) +3CI28) (2) PCl3lg)+Cl2lg) PCI5(g) K 0.0667 Kc 4.0...
Given the following reactions, (1) 2PC13(g) = 2P(g) + 3Cl2(g) (2) PC13(g) + Cl2(g) =PC15(g) Kc = 0.0667 Kc = 4.0 calculate Kc for the reaction below. (3) 2P(g) + 5C12(g) = 2PC15(8) Ke=??? 23 240 Oo oo 1.1 60
Question 4 1 pts Given the following reactions, (1) 2PC13(g) = 2P(g) + 3C12(8) (2) PC13(8) + Cl2(g) =PC15(8) K = 0.0667 Kc = 4.0 calculate K for the reaction below. (3) 2P(g) + 5C12() = 2PCi5(8) Kc = ??? 240 60 23 1.1 - Previous Next →
Question 4 2 pts Kc for the reaction below equals 125 at a particular temperature. F2(g) + Cl2(g) = 2 FCI(g) What is the value of K for the reaction given below? 1/2 F2(g) + 1/2 Cl2(g) = FCl(g) O K = 0.0894 OK - 11.2 O K = 0.0160 Ke = 62.5 O K = 125
Given the following reactions, (1) 1/2 N2(g) + 1/2 O2(g) ⇌ NO(g) Kc = 4.8×10^−10 (2) 2 NO(g) + O2(g) ⇌ 2 NO2(g) Kc = 9.1× 10^4 calculate Kc for the reaction below. (3) 2 NO2(g) ⇌ N2(g) + 2 O2(g) Kc = ???
3. Given Kc or Kp for the following reactions, what is the value of Kp or Ke? (a) 12 (g) + Cl2 (a) 22ICI (g): Kc = 2.0 x105 at 25°C (b) N204(g) + 2NO2(0); Kc = 0.90 at 120 °C (c) CaCO3(s) = Cao (s) + CO2 (ox Kp = 1.67 x 102 at 740 °C 4. A container contains an equilibrium mixture of H2 (g), 12(g), and Hl) at 721 K. The concentration of each substance present at...
help me by showing the work please Given the following information, Kc 2.0 x 10-38 Kc 2.4 x 101 2 NO(g) O2(g) 2 NO2 find the value of Ke for the following reaction: NO(g) + 03(g) NO2(g) + O2(g) A. 5.6 x 10-17 B. 3.5 x 1025 C. 9.0 x 1040 D. 1.1 x 10-4 practice Given the following information at 25°C, 2 NOCIg)2 NO(g) + Cl2(g) Kc 4.0 x 102 moV/L find the value of K for this reaction...
HQ14.41 consider the following reaction: PCI5 (g)-PCI3 (g) + Cl2 (g), with Kc-0.00183. Exactly 2.00 grams of PCI5 is placed into a 3.00 L flask. Calculate the equilibrium molarity concentration of Cl2 (g) O A0.00167 atm O B 0.00350 atm O C0.0437 atm O D 0.569 atm Unanswered 2 attemnts left
9. (1.2 pt) At a certain temperature the following reactions have the Kc constants shown; k, i = 4.2 x 1052 K. ii = 9.8 x 10128 K. = ???? → (i) S(s) + O2(g) SO2 (g) ㄹ (ii) 2 S (s) +3 O2 (g) 2SO3 (g) → Calculate the equilibrium constant Ke for the following reaction at the same temperature. 2502 (g) +02 (g) 2 SO3 (g) Kc
The Kc for the reaction at 298 K is given N2O4(g) ⇋ 2 NO2(g) Kc = 5.9 × 10–3 What is the Kc for the following reaction? ½ N2O4(g) ⇋ NO2(g) Kc = ?
2. How is the equilibrium-constant expression (Kc) for the reaction: 2NO(a) = N2() + Ke=0.145; related to the following reaction? O2 (a) N2(a) + O2(a) = 2NO(a) K=.............. (b) 4NOQ = 2Nz () + 2O2(g) Kos......... (c) NO) 1/2 N2(0)+ 1/2O2(0) K3= +++ (d) 1/2 N2(a) + 1/2O2(a) = NO) Ke=.............. 3. Given Kc or ko for the following reactions, what is the value of Koor K? (a) l2(g) + Cl2(a) = 2ICIOX Kc = 2.0 x105 at 25°C (b)...