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4.- I have 24 liters of gas in a piston at a temperature of 215 °C. If I cool the gas until the volume decreases to 10 liters
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4. from Vi = V2 Vi = 24L V2 = IOL T = 215°C = 215 + 273 =488k T2 = ? 24L CIOL 488k Tz Tz - 10*483 K = 203-33K T2 = 203.33–273

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